json怎么解析 json怎么解析数据

sql中json解析

你好！

with t as (select 'a:[{f:,h:,checindate:''month1：,year: ,day: '',checkoutdate:''month：,year: ,day: '',},

{checindate:''month2：,year: ,day: ,'',checkoutdate:''month：,year: ,day},

{checindate:''month3：,year: ,day: ,'',checkoutdate:''month：,year: ,day}]' str from dual)

,t1 as (SELECT substr(str,instr(str,'[')+1,instr(str,']')-instr(str,'[')-1) str FROM T)

,t2 as (select substr(str,instr(str,'{')+1,instr(str,'}')-instr(str,'{')-1) str from t1)

select str,substr(str,instr(str,'checindate')+12, instr(str,'checkoutdate')-instr(str,'checindate')-12) from t2;

得到第一个checindate，直接截取字符串就可以了

别搞得那么复杂了

C++json解析

代码示例：

#include <iostream>

#include <string>

#include <jsoncpp/json/json.h>

using namespace std;

int main()

{

string strJsonContent = "{\"role_id\": 1,\"occupation\": \"paladin\",\"camp\": \"alliance\"}";

int nRoleDd = 0;

string strOccupation = "";

string strCamp = "";

Json::Reader reader;

Json::Value root;

if (reader.parse(strJsonContent, root))

{

nRoleDd = root["role_id"].asInt();

strOccupation = root["occupation"].asString();

strCamp = root["camp"].asString();

}

cout << "role_id is: " << nRoleDd << endl;

cout << "occupation is: " << strOccupation << endl;

cout << "camp is: " << strCamp << endl;

return 0;

}